Asked by Neveah
Sickle cell anemia is a genetic blood disorder where red blood cells lose their flexibility and assume an abnormal, rigid, "sickle" shape, which results in a risk of various complications. If both parents are carriers of the disease, then a child has a 25% chance of having the disease, 50% chance of being a carrier, and 25% chance of neither having the disease nor being a carrier. If two parents who are carriers of the disease have 3 children, what is the probability that:
(a) two will have the disease?
(b) none will have the disease?
(c) at least one will neither have the disease nor be a carrier?
(d) the first child with the disease will the be 3rd child?
(a) two will have the disease?
(b) none will have the disease?
(c) at least one will neither have the disease nor be a carrier?
(d) the first child with the disease will the be 3rd child?
Answers
Answered by
PsyDAG
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
a. .25 * .25 * .75 = ?
b. .75^3 = ?
I'll leave c and d for you.
a. .25 * .25 * .75 = ?
b. .75^3 = ?
I'll leave c and d for you.
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