Asked by Sally

x^2 + x - 12
What is the minimum value of y?

Answers

Answered by John
This is a parabola.

(x+4)(x-3) = 0

x = -4 or x = 3 This is where you would be crossing the x axis.

You want the turning point which would be a minimum since this parabola opens upward. I know it opens up because the coeff. of x^2 is positive.

-b/2a = x -1/2 = -1/2 then find y

(-1/2)^2 -1/2 -12 = y
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