Question
You deposit $2500 at 4% interest. How long will it take to earn $3000?
Answers
Reiny
assuming compound interest
2500(1.04)^n = 3000
1.04^n = 1.2
use logs
n = log 1.2/log 1.04
= ...
2500(1.04)^n = 3000
1.04^n = 1.2
use logs
n = log 1.2/log 1.04
= ...
bobpursley
3000=2500(1.04)^t assuming annual interest compounded.
Take log of each side
log3000=log2500 + t log (1.04)
solve for t.
Take log of each side
log3000=log2500 + t log (1.04)
solve for t.