what is the height of the tank? You need to know how far above the top of the oil is the spout, and how deep is the oil.
Anyway, assuming the oil has a depth of d meters, and the spout is h meters above the top of the oil, then consider the oil as a stack of thin slices of thickness dy.
then the volume of a slice of oil is 81π dy m^3. That means the weight of the oil is
900*81π dy N
The work is weight * distance, so the total work involved is
∫[0,d] 72900π (h-y) dy
Consider the following depiction of a tank with radius r = 9 meters with a spout of height h = 4.5 meters.
A tank is half full of oil that has a density of 900 kg/m3. Find the work W required to pump the oil out of the spout. (Use 9.8 m/s2 for g and 3.14 for π. Round your answer to the nearest integer.)
1 answer
1 answer