Asked by House
A football is kicked with an initial velocity of 42 ft/sec at an angle of 35 degrees with the horizontal. How far has the football traveled horizontally after 0.5 sec? round to nearest tenth.
Could someone explain this please?
Could someone explain this please?
Answers
Answered by
House
x=t|v|cos(x)
x=t(42)cos35
x=42tcos35
y=t|v|sin(x)-1/2gt^2+h
y=t(42)sin35-1/2(32)t^2+0.5
y=42tsin35-16t^2+0.5
0.5=42tcos35
t=0.5/42cos35
t=0.00975181
I don't know, I just followed an example in my book.
x=t(42)cos35
x=42tcos35
y=t|v|sin(x)-1/2gt^2+h
y=t(42)sin35-1/2(32)t^2+0.5
y=42tsin35-16t^2+0.5
0.5=42tcos35
t=0.5/42cos35
t=0.00975181
I don't know, I just followed an example in my book.
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