Asked by House

A football is kicked with an initial velocity of 42 ft/sec at an angle of 35 degrees with the horizontal. How far has the football traveled horizontally after 0.5 sec? round to nearest tenth.

Could someone explain this please?

Answers

Answered by House
x=t|v|cos(x)
x=t(42)cos35
x=42tcos35

y=t|v|sin(x)-1/2gt^2+h
y=t(42)sin35-1/2(32)t^2+0.5
y=42tsin35-16t^2+0.5

0.5=42tcos35
t=0.5/42cos35
t=0.00975181

I don't know, I just followed an example in my book.
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