Question

a) am-an-2bn+2bm

b) 2ax-6bx+ay-3by

c) 2ax-6bx-ay+3by

d) a^2b+c^2b-c^2b-a^2b

e) a^3+3a^2+2a+6

f) ax-2ay+2bx-4by

Answer 1

I will do a couple , you do the rest following the same method

b)
2ax-6bx+ay-3by
= 2x(a - 3b) + y(a - 3b)
you MUST have the same binomial in each of the terms

= (a - 3b)(2x + y)

or

2ax + ay - 6bx - 3by)
= a(2x + y) - 3b(2x + y)
= (2x+y)(a - 3b)
showing that there is more than one way to do these

f) ax - 2ay + 2bx - 4by
= a(x - 2y) + 2b(x - 2y)
= (x-2y)(a+2b)