Question

From the top of a cliff overlooking a lake, a person throws two stones, as shown in the drawing. The cliff is 39.2 m high. The two stones described have identical initial speeds of v0 = 19.2 m/s and are thrown at an angle θ = 29.2 °, one below the horizontal and one above the horizontal. What is the distance between the points where the stones strike the water? Neglect air resistance.

Answer 1

The two will have the same x velocities (19.2 cos29.2), and the distance traveled will be that number times t. Find the two times by solving in y:
.5*-9.8t^2 + 19.2sin29.2t = -39.2
and
.5*-9.8t^2 - 19.2sin29.2 = -39.2