Asked by tonai
an open box is to be made by cutting small congruent squares from corners of a 12cm by 12cm . sheet of tin and bending up the sides . how large should the squares cut from the corners to be make the box hold as much as possible ?
Answers
Answered by
joan
no
Answered by
Tutor Allan
Let the Volume be V, and side of the square to be cut be x
V=x(12-x)^2
V=144x-48x^2+4x^3
dv/dx=144-96x+12x^2=0
12x^2-96x+144=0
x^2-8x+12=0
Solve for x
(x-2)(x-6)=0
x=2 0r x=6
V=x(12-x)^2
V=144x-48x^2+4x^3
dv/dx=144-96x+12x^2=0
12x^2-96x+144=0
x^2-8x+12=0
Solve for x
(x-2)(x-6)=0
x=2 0r x=6
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.