Asked by kefilwe

6 to the power 5 ÷ 6³+7 to the power zero
Answered by Damon
(6^5 /6^3) + 7^0 ???

6^2 + 1

37
Answered by Steve
If you mean

(6 to the power 5) ÷ (6³) + (7 to the power zero)

or, losing all the static

6^5 / 6^3 + 7^0
= 6^2 + 1
= 37

You may group otherwise, but the evaluations of the powers will be the same.
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