Question
An artificial satellite circles around the earth at the height where the gravitational force is one fourth of that at earth's surface. If the earth's radius is R the height of the satellite above the surface of the earth is?
Answers
Damon
r and Re
F = G Mm/r^2 = (.25) G Mm/Re^2
or
.25/Re^2 =1/r^2
.25 r^2 = Re^2
.5 r = Re
r = 2 Re
height = 2Re-Re = Re
F = G Mm/r^2 = (.25) G Mm/Re^2
or
.25/Re^2 =1/r^2
.25 r^2 = Re^2
.5 r = Re
r = 2 Re
height = 2Re-Re = Re