Combustion of 6.38 mg of ethylene glycol gives 9.06 mg CO2 and 5.58 mg H20. The compound contains only C, H, and O. What are the mass percentages of the elements in ethylene glycol?

Answer 1

make a mol fraction and then multiply by 100

Answer 2

but don't i have to know the formula for ethylene glycol?

Answer 3

check it online. and balance the equation

Answer 4

mass percent C = (mass C/mass sample)*100 =
Mass percent H = (mass H/mass sample)*100 =
Mass percent O = 100 -%C -%H.

Answer 5

My answer for the emperical formula is coming CHO but the answer is CH3O