Asked by Zack
                X is a point 7cm from the center of circle O with radius 9 cm. AXB is a chord of the circle such that AX= 2 XB. Find the length of AB.
            
            
        Answers
                    Answered by
            MathMate
            
    For the chord AB 
k=mXB
2k=mAX
We will construct diameter CD such that X lies on CD.
Now CX=9+7=16 cm, XD=9-7=2 cm
Using the theorem of intersecting chords (AB and CD), we have
16*2=k(2k)
Solve for k.
    
k=mXB
2k=mAX
We will construct diameter CD such that X lies on CD.
Now CX=9+7=16 cm, XD=9-7=2 cm
Using the theorem of intersecting chords (AB and CD), we have
16*2=k(2k)
Solve for k.
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