What ?
what is the function ?
Use parentheses if needed.
Find for dy/dx 4 – xy = y^3.
2 answers
as written,
-y - xy' = 3y^2 y'
(3y^2+x)y' = -y
y' = -y/(3y^2+x)
-y - xy' = 3y^2 y'
(3y^2+x)y' = -y
y' = -y/(3y^2+x)
1 answer