A 26 meter guy wire is attached to an upright pole 24 meters from the ground. How far from the pole must the wire be anchored in the ground?

2 answers

a^2 + b^2 = c^2

24^2 + b^2 = 26^2

576 + b^2 = 676

b^2 = 100

b = 10 meters
x² = 26² - 24²

this is actually a Pythagorean triple...5-12-13
in this case...10-24-26