a^2 + b^2 = c^2
24^2 + b^2 = 26^2
576 + b^2 = 676
b^2 = 100
b = 10 meters
A 26 meter guy wire is attached to an upright pole 24 meters from the ground. How far from the pole must the wire be anchored in the ground?
2 answers
x² = 26² - 24²
this is actually a Pythagorean triple...5-12-13
in this case...10-24-26
this is actually a Pythagorean triple...5-12-13
in this case...10-24-26