Asked by jan

the price p and the quantity x sold of a certain product obey the demand equation

p=(-1/3)x + 100

o is < or equal to x < or equal to 300




A) express revenue R as a function of x

b) what quantity x maximizes revenue.
Answered by bobpursley
Revenue=p*x
you finish..

Take the deriviative of R with respect to x, set to zero, solve for x.
Answered by jan
so would the revenue be

(-1/3)x + 100 * 300

I don't understand- how would you multiply by x is its inequalities?

Also, what is the deriviative?
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