I don't know how to go about this question. The number of elephants in a park is estimated to be
p(t)=7500/(1+749e^-0.15t)
Where t is the time in years and t=0 corresponds to the year 1930. Find the inverse p(t) and the interpretation of that.
2 answers
http://www.jiskha.com/display.cgi?id=1453991598
inverse would be time for a specific population
1+749 e^-.15t = 7500/p
749 e^-0.15 t = (7500-p)/p
e^-.015 t = (7500-p)/(749 p)
e^.015t = 749 p/(7500-p)
.015 t = ln [ 749 p] - ln [7500-p)]
t = 66.7 [ln 749 p - ln(7500-p)]
we had 10 when t was 0
so check
t = 66.7[ ln 7490 - ln 7490 ]
so yes, at least it checks when t = 0
1+749 e^-.15t = 7500/p
749 e^-0.15 t = (7500-p)/p
e^-.015 t = (7500-p)/(749 p)
e^.015t = 749 p/(7500-p)
.015 t = ln [ 749 p] - ln [7500-p)]
t = 66.7 [ln 749 p - ln(7500-p)]
we had 10 when t was 0
so check
t = 66.7[ ln 7490 - ln 7490 ]
so yes, at least it checks when t = 0