Asked by Selena

An 1750 kg weather satellite moves in a circular orbit with a gravitational potential energy of 1.69 x 10^10 J. At it's location, free-fall acceleration is only 6.44 m/s^2. How high above Earth's surface is the satellite?

Answers

Answered by Scott
the radius of the Earth is 6.37E3 km

gravitational force is inversely proportional to the square of the distance

9.81 * (6.37E3)² = 6.44 * (6.37E3 + h)²
Answered by Anonymous
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