An 1750 kg weather satellite moves in a circular orbit with a gravitational potential energy of 1.69 x 10^10 J. At it's location, free-fall acceleration is only 6.44 m/s^2. How high above Earth's surface is the satellite?

Answer 1

the radius of the Earth is 6.37E3 km

gravitational force is inversely proportional to the square of the distance

9.81 * (6.37E3)² = 6.44 * (6.37E3 + h)²

Answer 2

I D K