An airplane flying horizontally 1000 meters above the ground at 200 km per hr drops a bomb on a target on the ground. Determine the acute angle between the vertical and the line joning the airplaod and target at the instant when the bomb is released.

Answer 1

t equals the fall time

0 = -4.9 t² + 1000

horizontal distance to target
d = t * 200 km/hr

convert km/hr to m/s

the tangent of the angle is the height of the plane, divided by the horizontal distance to target