Asked by Angel
An airplane flying horizontally 1000 meters above the ground at 200 km per hr drops a bomb on a target on the ground. Determine the acute angle between the vertical and the line joning the airplaod and target at the instant when the bomb is released.
Answers
Answered by
Scott
t equals the fall time
0 = -4.9 t² + 1000
horizontal distance to target
d = t * 200 km/hr
convert km/hr to m/s
the tangent of the angle is the height of the plane, divided by the horizontal distance to target
0 = -4.9 t² + 1000
horizontal distance to target
d = t * 200 km/hr
convert km/hr to m/s
the tangent of the angle is the height of the plane, divided by the horizontal distance to target
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