Asked by Aaradhya
the fourth term of an ap is 11 And the eight term exceeds twice the fourth term by 5.find the ap and sum of first 20 terms.
Answers
Answered by
Steve
T4 = 11
T8 = 2*11+5 = 27
so, T8-T4 = 4d = 16
d = 4
a+3d = 11, so a = -1
S20 = 20/2 (2a+19d) = ...
T8 = 2*11+5 = 27
so, T8-T4 = 4d = 16
d = 4
a+3d = 11, so a = -1
S20 = 20/2 (2a+19d) = ...
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