Asked by Cydney
What is the formula for the nth term for the following sequence: 40, 16, 6.4, 2.56, 1.024, 0.4096?
Answers
Answered by
Steve
recall that
4^1=4
4^2=16
4^3=64
But, each term is multiplied by 10,1,.1,... = 10^(2-n)
so, Tn = 4^n * 10^(2-n) = 100 (4/10)^n
4^1=4
4^2=16
4^3=64
But, each term is multiplied by 10,1,.1,... = 10^(2-n)
so, Tn = 4^n * 10^(2-n) = 100 (4/10)^n
Answered by
shredder
40 / (2.5 ^ n-1)
Answered by
Afeez
Yeah
Answered by
Afeez
Shredder is correct .steve is not correct
Answered by
Steve
Ahem.
40/(2.5^n-1)
= 40*2.5/2.5^n
= 100/2.5^n
= 100 / (10/4)^n
= 100 * (4/10)^n
40/(2.5^n-1)
= 40*2.5/2.5^n
= 100/2.5^n
= 100 / (10/4)^n
= 100 * (4/10)^n
Answered by
Afeez
Steve dat nt it . Try this one . .a/2.5^n -1.0 . To check maybe it goes along wit d ques. And is this ogonna
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