Asked by vincent
John pushes on a 400 kg refrigerator with a force of 800 N. While sliding a friction force of 300 N acts on the refrigerator. What is the acceleration of this refrigerator?
Answers
Answered by
Damon
F = 800 - 300 = 500 N
a = F/m = 500/400 = 1.25 m/s^2
a = F/m = 500/400 = 1.25 m/s^2
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