Asked by Cruz

The back of George's property is a creek. George would like to enclose a rectangular area, using the creek as one side and fencing for the other three sides, to create a pasture. If there is 300 feet of fencing available, what is the maximum possible area of the pasture.
Answered by bobpursley
300=2w+L
L=300-2w

area=Lw=w(300-2w)
Notice this is a parabola. It's two zeroes are at w=0, and w=150

Because of symettry, the max must be halfway between the zeroes, so at max area, w=75

Area=75(150) max
Answered by Colonel
since the creek forms the fourth side of the pasture, fencing is required only for the other three sides

the max area is 10,000 sq ft, since each of the three fenced sides has length 100 ft

100 ft x 100 ft = 10,000 ft^2



Answered by bobpursley
amazing, I found an area above of 11250. Math analysis is a gift from God.
Answered by Reiny
I agree with Bob
Answered by Steve
Normal and <small>small</small> text
Answered by jolly rancher
oops - thought I read a square was required - sorry and may God come to your assistance with math