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An experiment being conducted, the pressure is 0.9 atm and the temperature is 18 ° C. One of the steps of experience requires t...Asked by Kennia
An experiment being conducted, the pressure is 0.9 atm and the temperature is 18 ° C. One of the steps of
experience requires the combustion of 500 ml of ethanol (d = 0.78 g / ml). Whereas the burning this amount of ethanol does not significantly alter the enviroments conditions, but releases carbon dioxide. Calculate the volume of CO2 generated (in L) and the CO2 concentration in mol / L
experience requires the combustion of 500 ml of ethanol (d = 0.78 g / ml). Whereas the burning this amount of ethanol does not significantly alter the enviroments conditions, but releases carbon dioxide. Calculate the volume of CO2 generated (in L) and the CO2 concentration in mol / L
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Answered by
DrBob222
C2H5OH + 3O2 ==> 2CO2 + 3H2O
Determine mass ethanol from density.
mass = volume x density
mass = approx 400 but you need a more accurate answer than that.
mols ethanol = grams/molar mass = about 9 mols. Again you need to confirm an accurate answer.
For every 1 mol ethanol burned you get 2 mols CO2 so mols CO2 produced = approx 18.
Use PV = nRT to calculate volume in L.
(CO2) = mols/L. Plug in your value for mols and L to solve for (CO2).
Post your work if you get stuck.
Determine mass ethanol from density.
mass = volume x density
mass = approx 400 but you need a more accurate answer than that.
mols ethanol = grams/molar mass = about 9 mols. Again you need to confirm an accurate answer.
For every 1 mol ethanol burned you get 2 mols CO2 so mols CO2 produced = approx 18.
Use PV = nRT to calculate volume in L.
(CO2) = mols/L. Plug in your value for mols and L to solve for (CO2).
Post your work if you get stuck.
Answered by
Kennia
and molarity of CO2 ?
Answered by
DrBob222
I did that above.
(CO2) is read as concentration of CO2 in mols/L = M
(CO2) is read as concentration of CO2 in mols/L = M
Answered by
Kennia
Thank you :)
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