Asked by Rissa
Dave Bowers collects U.S. gold coins. He has a collection of 54 coins. Some are $10 coins, and the rest are $20 coins. If the face value of the coins is $780, how many of each denomination does he have?
Answers
Answered by
Scott
t for ten and w for twenty
t + w = 54
10 t + 20 w = 780
solve the system
t + w = 54
10 t + 20 w = 780
solve the system
Answered by
Afeez
10x +20y =780. X + y =54 . Solve simultaneously x=30 and y=24. . . If u wana knw hw many gold coin7 itz lyk dis 10 x 30=$300and 20 x 24 =$480
Answered by
Henry
X = $10-coins.
54-x = $20-coins.
10x + 20(54-x) = 780.
10x + 1080 - 20x = 780.
-10x = -300.
X = 30.
54-x = 54-30 = 24
54-x = $20-coins.
10x + 20(54-x) = 780.
10x + 1080 - 20x = 780.
-10x = -300.
X = 30.
54-x = 54-30 = 24
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