Asked by Alan
An aluminum sheet used for food preservation weighs about 0.05 g/cm-2 How many electrons are in a 1 cm2 of this sheet?
Answers
Answered by
bobpursley
Each atom of aluminum has 13 electrons.
electrons=13*atomsAl
= 13*avagNumber*molesAL
= 13*6.022E23(.05g/cm^2*1cm^2/27)
electrons=13*atomsAl
= 13*avagNumber*molesAL
= 13*6.022E23(.05g/cm^2*1cm^2/27)
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