Asked by Monica
Each of the two congruent sides of an isosceles triangle are 10 centimeters more than 1/2 the length of the base. If the perimeter of the triangle is to be at most 100 centimeters, what is the maximum length of the base?
Answers
Answered by
Damon
2 [ (b/2)+10 ] + b </= 100
b + 20 + b </= 100
2 b </= 80
b </= 40
so 40 cm
b + 20 + b </= 100
2 b </= 80
b </= 40
so 40 cm
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