Question
Which THE PH VALUE OF A solution 0,01 mol/l a monoacido that presents ka= 1×10-6
Answers
bobpursley
Well, the equation is
HA<<>>>H+ + A-
and ;etting x be the concentration of H+ and A- then
ka=x^2/(.01-x)
and put in Ka, and solve for x. It is a quadratic equaion.
Once you have x, then
pH=-log(x)
HA<<>>>H+ + A-
and ;etting x be the concentration of H+ and A- then
ka=x^2/(.01-x)
and put in Ka, and solve for x. It is a quadratic equaion.
Once you have x, then
pH=-log(x)
Angelica
Thank you so much