Question

Bailey is on the tenth frame of her recent bowling competition and she needs to pick up the last pin for a spare and the first place trophy. She rolls the 7.05-kg ball down the lane and it hits the 1.53-kg pin head on. the ball was moving at 8.24 m/s before the collision. The pin went flying forward at 13.2 m/s. Determine the post collision speed of the ball

Answer 1

momentum is conserved

Mb * V1b = (Mb * V2b) + (Mp * Vp)

Answer 2

initial momentum
= 7.05*8.24 + 0

final momentum
= 7.05 * v + 1.53*13.2

final momentum = initial momentum