x + 2y = 11
2x + 3y = 50
double the first , then subtract to get y
Once you have that , plug into the first to get x
Two numbers. The first plus twice the second equals 11. Twice the first plus three times the second equals 50. What are the numbers?
2 answers
double the first EQUATION , then subtract THE 2ND EQUATION to get y
2x + 4y - 2x - 3y = 22 - 50
y = -28
substitute into the 1st equation to find x
2x + 4y - 2x - 3y = 22 - 50
y = -28
substitute into the 1st equation to find x