Asked by Godiraona

Please help me with these bodmas sums
8-3×(17-8)
32÷[5-(4-7)]
12-[6-(3+8)×2]
3+7×(2-4)
Answered by Reiny
you do not have to type the ×
in
8-3×(17-8) , just say 8 - 3(17-8)

I will do the most complicated looking one, you try the rest.

12-[6-(3+8)×2]
= 12 - [6 - (11)(2)]
= 12 - [6-22]
= 12 - [-16]
= 12 + 16
= 28
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