Asked by mbali
8th grade homework: 3 digits, divisible by 5, odd number, product of the digits is 15, sum of the digits is less than 10 and it less than 12 by 12.
Answers
Answered by
Damon
ends in 5 or 0
odd, so ends in 5
100 a + 10 b + c
We know c = 5
100 a + 10 b + 5
a b 5 = 15
or a b = 3
a + b <5
100a + 10 b < 144
so a = 1
since a b = 3, b = 3
so
135
odd, so ends in 5
100 a + 10 b + c
We know c = 5
100 a + 10 b + 5
a b 5 = 15
or a b = 3
a + b <5
100a + 10 b < 144
so a = 1
since a b = 3, b = 3
so
135
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