length of floor of dining space=400cm
breadth=300cm
area=400×300
=120000cm^2
length of tile=8cm
breadth=5cm
area of one tile =8×5
=40cm^2
tiles required =120000/40
=3000 tiles
How many tiles of length 8cm breath 5cm are needed to tile a floor of dining space which is 400 cm long and 300 cm wide
2 answers
If we lay the tiles so the the length of the tile falls along the 4 m floor length, then we need 400/8 or 50 tiles along the length, and 300/5 or 60 tiles along the width.
Which is 50x60 or 3000 tiles, just like anjali had
but if we lay the width along the 400 cm length, we will need
400/5 or 80 tiles along that way, and
300/8 or 37.5 rows of tiles the other way.
Which means we have to cut some tiles
and we will need 80x38 or 3040 tiles.
Which is 50x60 or 3000 tiles, just like anjali had
but if we lay the width along the 400 cm length, we will need
400/5 or 80 tiles along that way, and
300/8 or 37.5 rows of tiles the other way.
Which means we have to cut some tiles
and we will need 80x38 or 3040 tiles.