Asked by Anu
A bag contains 4 white beads and one black bead. Three beads are removed from the bag individually being replaced before each selection .find the probability that from the three beads there are at least two black beads
Answers
Answered by
Reiny
At each draw,
prob(white) = 4/5
prob(black) = 1/5
so you want 2 blacks or 3 blacks
= C(5,2) (1/5)^2 (4/5) + C(5,3) (1/5)^3
= ....
you push the calculator buttons
prob(white) = 4/5
prob(black) = 1/5
so you want 2 blacks or 3 blacks
= C(5,2) (1/5)^2 (4/5) + C(5,3) (1/5)^3
= ....
you push the calculator buttons
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