Asked by Anjali
a rain drop of radius 0.3mm has a terminal velocity in air 1m/s. the viscosity of air is 18×10^-5 dyne cm^-2 s. find the viscous force on the rain drops in newton.
Answers
Answered by
sachi
F=6pie.n.r.v
=6*(3.14)*18*10^-5*0.3*10^-3*1
=1017.3*10^-4N
=6*(3.14)*18*10^-5*0.3*10^-3*1
=1017.3*10^-4N
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