Question

What is the y-intercept of y =
2/3x + 2?

I have to write it out but how?


A line has a slope of
1/2 and passes through the point (0,5). What is the equation of the line?

A)y = 1/2x + 5

B)y = 1/2x - 5<---

C)y = 5x + 1/2

D)y = -5x + 1/2

Find an equation of the line that passes through the points (1,2) and (2,3).

A) y = x - 1
B) y = x + 1
C) y = x - 2 <--
D) y = 2x - 1

8)Find an equation of the line that has intercepts (1,0) and (0,4).
A) y = 4x - 1 <--
B) y = -4x + 4
C) y = -4x + 1
D) y = -4x - 4

9)A line passes through the point (2, 3) and has a slope of -2. Which is the equation of the line in point-slope form?

A) 2x + y = 7
B) y = -2x + 7
C) y - 3 = -2(x - 2)<---
D) y = -1/2x + 5

Answer 1

What is the y-intercept of y =
2/3x + 2?

I have to write it out but how?
------------------------------

The y axis intercept is where x = 0

which in this case is 2

and I think you meant to type
y = (2/3) x + 2
because what you typed was
y = 2/(3x) + 2
think parentheses when you try to express equations with a keyboard.

Answer 2

It's
y = two-thirds x + 2

Answer 3

its -2

Answer 4

Y = (2/3)x + 2

x = 0 at the point where the graph crosses the y-axis. So in the Eq above, replace x with 0 and solve for y:

Y = (2/3)*0 * 2 = 0 + 2 = 2.
(x,y) = (0,2).

Answer 5

2. Given: P(0,5), m = 1/2.
Y = mx + b = 5.
(1/2)*0 + b = 5, b = 5.
Eq: Y = (1/2)x + 5.

3. Given: (1,2), (2,3).
m = (3-2)/(2-1) = 1/1 = 1.
Y = mx + b = 2.
1*1 + b = 2, b = 1.
Eq: Y = x + 1.

8. Same procedure as #3.

9. Given: (2,3), (x,y), m = -2.
m = (y-3)/(x-2) = -2.
Cross multiply:
y-3 = -2(x-2).