CH4 + 2O2 ==> CO2 + H2O
dHrxn = (n*dHformation products) - (dHformation reactants) = ? = q for 1 mol CH4.
volume of house = 3000cm*3000cm*300cn = ? cc.
mols air = ?cc/22,400 = ?
How many Joules (or kJ) do you need to heat the house.
That's q needed = mols air x specific air (in J/mol) x delta T.
Then q for 1 mol CH4 x ?mols CH4 = qneeded.
Solve for number mols CH4 and convert to grams. Checl this against your work.
Combustion of natural gas (primarily methane) occurs in most household heaters. The heat given off in this reaction is used to raise the temperature of the air in the house. Assuming that all the energy given off in the reaction goes to heating up only the air in the house, determine the mass of methane required to heat the air in a house by 10.0 degrees C. Assume each of the following: house dimensions are 30.0 m x 30.0 m x 3.0 m; specific heat capacity of air is 30 J/k•mol; 1.00 mol of air occupies 22.4 L for all temperatures concerned.
My answer: 649 g
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