Asked by Sara
A line crosses the y-axis at (0,4) and has a slope of -2. Find an equation for the this line.
A) y = 2x + 4
B) y = -2x + 4
C) y = -2x - 4
D) y = -4x + 2 <--
6)Write the equation of the line with the given slope and y-intercept.
slope = 5
y-intercept = 8
A) y = 5x + 8
B) x = 5y + 8 <--
C) y = 8x + 5
D) x = 8y + 5
A) y = 2x + 4
B) y = -2x + 4
C) y = -2x - 4
D) y = -4x + 2 <--
6)Write the equation of the line with the given slope and y-intercept.
slope = 5
y-intercept = 8
A) y = 5x + 8
B) x = 5y + 8 <--
C) y = 8x + 5
D) x = 8y + 5
Answers
Answered by
bobpursley
neither is correct.
Y=slope*x + yintercept
Y=slope*x + yintercept
Answered by
Damon
slope of -2. !!!!!!!!!!
THAT means m = -2
in y = m x + b
y = -2 x + b
moreover you are told that when x = 0, y = +4
The second one is correct
THAT means m = -2
in y = m x + b
y = -2 x + b
moreover you are told that when x = 0, y = +4
The second one is correct
Answered by
Damon
sorry, you have x and y reversed in the second one.
Answered by
Sara
@bobpursley thanks.
@Damon so the 2nd one is B, and for the first one its B. -2x + 4
@Damon so the 2nd one is B, and for the first one its B. -2x + 4
Answered by
Sara
no wait is 2x+4.
Answered by
Damon
first one y = -2x + 4 which is B
m = -2
b = 4
second one
y = 5 x + 8
which is A
m = -2
b = 4
second one
y = 5 x + 8
which is A
Answered by
leo
-3 and crosses the vertical axis at (0, 4).
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