Asked by SkatingDJ
In an isosceles triangle, the perimeter is 8 more than 2 times on of the legs. If the perimeter is 28 in, find the length of the base.
A. 16 in
B. 18 in
C. 10 in
D. 8 in
Given triangle ABC with A(-3, 2), B(-1, -4), and C(4, 1), write the equation for the line containing altitude line AR in standard form.
A. x - y = 1
B. x + y = -1
C. x + y = 1
D. x - y = -1
Given triangle ABC with A(-3, 4), B(5, 8), and C(2, -2), write the equation of the line containing midsegment line XZ in standard form, where X is the midpoint of line AB and Z is the midpoint of line BC.
A. 6x - 5y = -24
B. 2x + 5y = 32
C. 2x - 5y = -28
D. 6x + 5y = 36
What is the image of O(-2, -1) after two reflections, first across the line y = -5, then across the line x = 1?
A. (-2, -1)
B. (-1, -6)
C. (4, -9)
D. (1, -5)
These are the only questions that I need help on for this test! I can't seem to solve them, I really need help!!! Please help? Thanks!
A. 16 in
B. 18 in
C. 10 in
D. 8 in
Given triangle ABC with A(-3, 2), B(-1, -4), and C(4, 1), write the equation for the line containing altitude line AR in standard form.
A. x - y = 1
B. x + y = -1
C. x + y = 1
D. x - y = -1
Given triangle ABC with A(-3, 4), B(5, 8), and C(2, -2), write the equation of the line containing midsegment line XZ in standard form, where X is the midpoint of line AB and Z is the midpoint of line BC.
A. 6x - 5y = -24
B. 2x + 5y = 32
C. 2x - 5y = -28
D. 6x + 5y = 36
What is the image of O(-2, -1) after two reflections, first across the line y = -5, then across the line x = 1?
A. (-2, -1)
B. (-1, -6)
C. (4, -9)
D. (1, -5)
These are the only questions that I need help on for this test! I can't seem to solve them, I really need help!!! Please help? Thanks!
Answers
Answered by
Steve
In any isosceles triangle, the perimeter is the base plus 2 times one of the legs. Clearly the base here is 8.
No idea where R is.
X = (A+B)/2 = (1,6)
Z = (B+C)/2 = (7/2,3)
XZ in two-point form is
y-6 = (-6/5)(x-1)
Now just rearrange that into standard form.
across y = -5: (x,y)->(x,-10-y)
across x = 1: (x,y)->(2-x,y)
both: (x,y)->(2-x,-10-y)
So, (-2,-1)->(4,-9)
No idea where R is.
X = (A+B)/2 = (1,6)
Z = (B+C)/2 = (7/2,3)
XZ in two-point form is
y-6 = (-6/5)(x-1)
Now just rearrange that into standard form.
across y = -5: (x,y)->(x,-10-y)
across x = 1: (x,y)->(2-x,y)
both: (x,y)->(2-x,-10-y)
So, (-2,-1)->(4,-9)
Answered by
SkatingDJ
Thanks Steve!
(But I STILL need help figuring out the AR one... gonna repost that question)
(But I STILL need help figuring out the AR one... gonna repost that question)
Answered by
I <3 YOU
the amount of people who have seen this but havent said dip ship
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.