Asked by Mahnoor
in todays experiment what length of magnesium ribbon would be required to generate 42.00 ml's of H2?
Answers
Answered by
bobpursley
determine the mass...
Mg+2HCl>>>MgCl2 + H2
at stp (your conditions not known), 42ml H2 equivalent to .042/22.4 moles, or .042*23/22.4 grams Mg.
Length=massMg/(mass/length)
sometimes on Mg ribbon, the mass /length is labeled on the container, but you can determine it by massing measuring a known length.
Mg+2HCl>>>MgCl2 + H2
at stp (your conditions not known), 42ml H2 equivalent to .042/22.4 moles, or .042*23/22.4 grams Mg.
Length=massMg/(mass/length)
sometimes on Mg ribbon, the mass /length is labeled on the container, but you can determine it by massing measuring a known length.
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