4*10^-6 C*1 electron/(1.6*10^-19C)
= (4/1.6) 10^13 electrons
How many excess electrons are on this bal- loon? The elemental charge is 1.6 × 10−19 C.
Answer in units of electrons.
= (4/1.6) 10^13 electrons
Given:
Charge on the balloon (in Coulombs) = 4 μC = 4 × 10^(-6) C
Elemental charge of an electron = 1.6 × 10^(-19) C
Number of excess electrons = (Charge on the balloon) / (Elemental charge of an electron)
Number of excess electrons = (4 × 10^(-6) C) / (1.6 × 10^(-19) C)
To simplify the calculation, we can divide the numerator and denominator by 10^(-19):
Number of excess electrons = (4 × 10^(-6) / 10^(-19)) / (1.6 × 10^(-19) / 10^(-19))
Number of excess electrons = 4 / 1.6
Number of excess electrons = 2.5 × 10^19 electrons
Therefore, the number of excess electrons on the balloon is approximately 2.5 × 10^19 electrons.
The elemental charge is given as 1.6 × 10^(-19) C. This means that one elementary charge is equivalent to 1.6 × 10^(-19) C.
To find the number of excess electrons on the balloon, we can divide the total charge of the balloon (4 μC) by the elementary charge (1.6 × 10^(-19) C):
(Number of excess electrons) = (Total charge of balloon) / (Elementary charge)
(Number of excess electrons) = (4 μC) / (1.6 × 10^(-19) C)
Now let's perform the calculation:
(Number of excess electrons) = (4 × 10^(-6) C) / (1.6 × 10^(-19) C)
We can simplify this calculation by canceling out units:
(Number of excess electrons) = (4 × 10^(-6)) / (1.6 × 10^(-19))
To divide these numbers with exponents, we subtract the exponent of the denominator from the exponent of the numerator:
(Number of excess electrons) = 4 × 10^(-6 + 19)
(Number of excess electrons) = 4 × 10^(13)
Thus, the number of excess electrons on the negatively charged balloon is 4 × 10^13 electrons.