How do you get g(2x)=8 at x=1?
g(2) = 4
Anyway, take a peek here and I think it will become clear. Just be sure to include that final 2 for the g(2x) instead of g(x).
http://www.calculus-help.com/6-table-derivatives/
scroll down to the end.
Use the table below to evaluate d/dx [f[g(2x)]] at x = 1
x 1 2 3 4
f(x) 6 1 8 2
f '(x) 6 1 8 2
g(x) 1 4 4 3
g '(x) 9 5 5 -4
I don't know how to continue with this question. i know [g(2x)]=8...pretty sure
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