Asked by Claire
2AgNO3 + CaCl2 ---> Ca(NO3)2 + 2AgCl
all of the substances involved in this reaction are soluble in water except AgCl which forms a solid at the bottom of the flask . Suppose we mix together a solution containing 12.6 g of AgNO3 and one containing 8.4 g of CaCl2 .What mass of AgCl is formed?
all of the substances involved in this reaction are soluble in water except AgCl which forms a solid at the bottom of the flask . Suppose we mix together a solution containing 12.6 g of AgNO3 and one containing 8.4 g of CaCl2 .What mass of AgCl is formed?
Answers
Answered by
DrBob222
This is a limiting reagent (LR) problem.
mols AgNO3 = grams/molar mass = ?
mols CaCl2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols AgNO3 to mols AgCl.
Do the same to convert mols CaCl2 to mols AgCl.
It is likely the two values for mols AgCl will not agree which means both answers can't be right. The correct value in LR problems is ALWAYS the smaller value. Choose that number and convert to grams AgCl. grams AgCl = mols AgCl x molar mass AgCl.
mols AgNO3 = grams/molar mass = ?
mols CaCl2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols AgNO3 to mols AgCl.
Do the same to convert mols CaCl2 to mols AgCl.
It is likely the two values for mols AgCl will not agree which means both answers can't be right. The correct value in LR problems is ALWAYS the smaller value. Choose that number and convert to grams AgCl. grams AgCl = mols AgCl x molar mass AgCl.
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