Asked by Maryam
A block of mass m1=3.70kg on a frictionless plane inclined at angle 30 deg is connected by a cord over a massless, frictionless pulley to a second block mass m2= 2.30kg. What is...
a) The magnitude of the acceleration of each block?
b) The direction of the acceleration of the hanging block?
c) The tension in the cord?
a) The magnitude of the acceleration of each block?
b) The direction of the acceleration of the hanging block?
c) The tension in the cord?
Answers
Answered by
Damon
LOL - I guess unless the string breaks they better have the same acceleration
force of m1 down slope =
3.7 g sin 30 = 1.85 g
force of m2 the other way = 2.3 g
net force = (2.3 -1.85)g
= .45 * 9.81 = 4.41 N block 2 wins and heads straight down, block 1 heads up slope
a = 4.41 /(3.7+2.3) = .736
block 1 up, block 2 down
look at block 2
2.3 a = 2.3(9.81) - T
T = 2.3 (9.81 -.736)
T = 20.9 Newtons tension
force of m1 down slope =
3.7 g sin 30 = 1.85 g
force of m2 the other way = 2.3 g
net force = (2.3 -1.85)g
= .45 * 9.81 = 4.41 N block 2 wins and heads straight down, block 1 heads up slope
a = 4.41 /(3.7+2.3) = .736
block 1 up, block 2 down
look at block 2
2.3 a = 2.3(9.81) - T
T = 2.3 (9.81 -.736)
T = 20.9 Newtons tension
Answered by
John
This didn't work for me!!!!
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