Asked by Rabie

a+b+c=28
b= a+3
I plugged in the b but got stuck on 2a+3+c.
What I did:
a+a+3+c=28
2a+3+c=28, but what do I do next to solver this linear equation?

Answers

Answered by Reiny
since you have 3 unknowns you will need 3 distinct equations.
I see only two.

so all you can do is say:
2a + c = 25
Answered by Rabie
Oh the third equation was
a+3b+10c=131
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions