Question

Three equal positive point charges q are at the corners of an equilateral triangle with sides of length a. What is the magnitude and direction of the electric field at one corner of the triangle due to two charges placed on another two corners of the triangle ?. These two corners are placed on the horizontal side of the triangle.

Answer 1

E1 = kq/a1(sqr) at angle of 60
E2 = kq/a2(sqr) at angle of 120
x components cancel
y components sum = 2(cos30)kq/a(sqr)