Asked by tracia
Calcium carbonate was reacted with hydrogen chloride. What is the percentage yield of carbon(iv)oxide produced if 3.65g of the gas is collected when 10g of calcium(iii)oxocarbonate reacts
Answers
Answered by
DrBob222
First there is no such thing as calcium(iii) oxycarbonate. Ditto for calcium(iv) oxide.
CaCO3 + 2HCl ==> H2O + CO2 + CaCl2
mols CaCO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CaCO3 to mols CaO.
Convert mols CaO to grams CaO by grams = mols x molar mass = ?. This is the theoretical yield (TY). The actual yield (AY) given in the problem is 3.65.
%yield = (AY/TY)*100 = ?
CaCO3 + 2HCl ==> H2O + CO2 + CaCl2
mols CaCO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CaCO3 to mols CaO.
Convert mols CaO to grams CaO by grams = mols x molar mass = ?. This is the theoretical yield (TY). The actual yield (AY) given in the problem is 3.65.
%yield = (AY/TY)*100 = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.