Question

If the velocity is given as v=t^2-2t+2 what is the acceleration when v=10m/s?

Answer 1

a = dv/dt = 2 t - 2

if you really mean when v = 2 we have to go back and find the times when v = 2
2 = t^2 - 2 t + 2

t^2 - 2 t = 0
t(t-2) = 0
t = 0 or t = 2
so
a = 2 t - 2
= -2
or
= 2

Answer 2

I mean when(2t-2) when v = 10
10 = t^2 -2t + 2

t^2 - 2 t - 8 = 0

(t+2)(t-4) = 0
use + t
so t = 4

a = 2 t - 2 = 6