since 9 = 3^2,
log3(n) = 2log9(n)
That is, the power of 3 needed for a number is twice as big as the power of 9.
So, we have
2log9(x) = log9(6x)
log9(x^2) = log9(6x)
x^2 = 6x
x = 0 or 6
0 not allowed, so x=6
Log3(x)=log9(6x)
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