Asked by nina
Solve the system by either substitution or elimination
3x-5y=21
2x+y=1
A (2,-3)
B (2,3)
C (-2,-1)
D (-2,1)
3x-5y=21
2x+y=1
A (2,-3)
B (2,3)
C (-2,-1)
D (-2,1)
Answers
Answered by
Steve
multiply the 2nd equation by 5 and you have
3x-5y = 21
10x+5y = 5
Now you can eliminate y and get x, then figure y.
3x-5y = 21
10x+5y = 5
Now you can eliminate y and get x, then figure y.
Answered by
Add em up
a (2, -3)
Answered by
aaahhhhhhhhhhhhhhhhhh
thanks you for helpful explanation
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