Asked by Roshini

A man is 4times old as his son.After 16years he will be only twice as old as his son.Find their present age.
Answered by Reiny
Son's present age --- x
Man's present age --- 4x

16 years from now:
son --> x+16
man --> 4x+16

solve ....

4x+16 = 2(x+16)
Answered by Trent
The son is 8 years old.
4x+16 = 2x+32
-16 -16
4x = 2x+16
-2x -2x
2x = 16
*1/2 *1/2
x = 8

(4*8)+16 = 48
Father is 48 years old.
Answered by Justice
4*x=4+3*x
4x=4+3x
4x-3x=4
x=4
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